We are being asked to determine the maximum number of electronsin an atom for each set of quantum numbers offered.

You are watching: Which set of numbers gives the correct possible values of l for n = 2?

To deal with this difficulty, let’s initially specify and also determine the possible worths of the 4 quantum numbers:

principal quantum number (n)energy level in orbitals and its worth might be any kind of positive integerstarting from 1 to infinity.

angular momentum quantum number (ℓ)(l) has to be at leastern 1 less than n,array of values from0 approximately (n-1)

▪ Each ℓ valuecoincides to a subshell: Which collection of quantum numbers is correct and consistent through n = 4?

(A)l = 3 ml= -3 ms = +1/2

(B)l= 4 ml= +2 ms= -1/2

(C) l = 2 ml= +3 ms = +1/2

(D)l = 3 ml = -3 ms = +1

Q.What is the smallest acceptable worth for the absent quantum number?n = ?, ℓ = 2, mℓ = 0, ms = +1/2A) 4B) 3C) 1D) 5E) 2
Q.Which of the adhering to represents a collection of quantum number for valence electron of Chlorine?A. (3,1,0,-1)B. (3, 2, 0, -1/2)C. (3,0,2, 1/2)D. (3,1,-1, -...
Q.Each of the following sets of quantum numbers offers indevelopment on a particular orbital. Find the error in each. a) n = 4, l = 0 , m l = 1, m s = -1/2b...
Q.How many electrons have the right to have actually the adhering to quantum sets? a. In the 7 th shell of an atom (n = 7)b. n = 5, ℓ = 2c. n = 6, ℓ = 3, m ℓ = -2d. n = 4, ℓ = ...

What clinical idea carry out you need to know in order to resolve this problem?

Our tutors have actually suggested that to solve this trouble you will certainly must apply the Quantum Numbers: Spin Quantum Number principle. You deserve to watch video lessons to learn Quantum Numbers: Spin Quantum Number. Or if you need more Quantum Numbers: Spin Quantum Number practice, you have the right to also exercise Quantum Numbers: Spin Quantum Number exercise problems.

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Our tutors rated the obstacle ofWhich collection of quantum numbers is correct and also consistent via ...as high difficulty.

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Based on our data, we think this difficulty is pertinent for Professor Donovan's class at UAKRON.

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